A) \[\frac{{{l}_{0}}}{16}\]
B) \[\frac{{{l}_{0}}}{2}\]
C) \[\frac{{{l}_{0}}}{4}\]
D) \[\frac{{{l}_{0}}}{8}\]
Correct Answer: D
Solution :
\[{{l}_{2}}=\frac{{{l}_{0}}}{2}{{\cos }^{2}}{{45}^{o}}\] \[=\frac{{{l}_{0}}}{2}\times \frac{1}{2}\] \[=\frac{{{l}_{0}}}{4}\] \[{{l}_{3}}=\frac{{{l}_{0}}}{4}{{\cos }^{2}}{{45}^{o}}\] \[{{l}_{3}}=\frac{{{l}_{0}}}{8}\]You need to login to perform this action.
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