A) \[2.00H\]
B) \[0.51H\]
C) \[1.5H\]
D) \[0.99H\]
Correct Answer: B
Solution :
In an\[L-C-R\]circuit, the current and the voltage are in phase\[(\phi =0)\], when \[\tan \phi =\frac{\omega L-\frac{1}{\omega C}}{R}=0\] or \[\omega L=\frac{1}{\omega C}\] or \[L=\frac{1}{{{\omega }^{2}}C}\] Here,\[\omega =2\pi f=2\times 3.14\times 50{{s}^{-1}}=314{{s}^{-1}}\] and \[C=20\mu F=20\times {{10}^{-6}}F\] \[\therefore \] \[L=\frac{1}{(314{{s}^{-1}})\times (20\times {{10}^{-6}}F)}=0.51\,\,H\]You need to login to perform this action.
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