A) exactly at the target
B) \[10cm\] below the target
C) \[10cm\] above the target
D) \[5cm\] above the target
Correct Answer: D
Solution :
Distance \[=ut\] \[\Rightarrow \] \[t=\frac{s}{u}=\frac{50}{500}=0.1\,\,s\] \[\therefore \] \[h=0+\frac{1}{2}g\,\,{{t}^{2}}=\frac{1}{2}\times 10\times {{(0.1)}^{2}}\] \[=0.05m=5cm\] (above the target)You need to login to perform this action.
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