A) \[4.2\times {{10}^{2}}Wb/{{m}^{2}}\]
B) \[4.2\times {{10}^{-3}}Wb/{{m}^{2}}\]
C) \[4.2\times {{10}^{-4~}}Wb/{{m}^{2}}\]
D) \[4.2\times {{10}^{-5}}Wb/{{m}^{2}}\]
Correct Answer: A
Solution :
Intensity of field at a distance x from centre of loop \[F=\frac{{{\mu }_{0}}}{4\pi }\frac{2M}{{{x}^{3}}}=\frac{{{10}^{-7}}\times 2\times 2.1\times {{10}^{-25}}}{{{({{10}^{-10}})}^{3}}}\] \[=4.2\times {{10}^{-2}}Wb/{{m}^{2}}\]You need to login to perform this action.
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