A) isotope
B) isobar
C) isomer
D) isoneutronic
Correct Answer: A
Solution :
In the radioactive charge \[_{A}{{R}^{B}}{{\xrightarrow[{}]{-\alpha }}_{A-2}}{{X}^{B-4}}{{\xrightarrow[{}]{-\beta }}_{A-1}}{{Y}^{B-4}}\] \[{{\xrightarrow[{}]{-\beta }}_{A}}{{Z}^{B-4}}\] Where, A = atomic number B = mass number R and Z are isotopes due to the same atomic number.You need to login to perform this action.
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