A) 50
B) 100
C) 166.6
D) 150
Correct Answer: B
Solution :
The dissociation of\[X{{Y}_{2}}\]is as \[\underset{\begin{smallmatrix} \,\,\,\,\,600\,mm \\ 600-x\,mm \end{smallmatrix}}{\mathop{XY2(g)}}\,\underset{\begin{smallmatrix} 0 \\ x \end{smallmatrix}}{\mathop{XY(g)}}\,+\underset{\begin{smallmatrix} 0 \\ x \end{smallmatrix}}{\mathop{Y(g)}}\,\underset{\begin{smallmatrix} in\text{ }initial\text{ }at \\ equilibrium \end{smallmatrix}}{\mathop{{}}}\,\] If \[600-x+x+x=800mm\] \[x=200\text{ }mm.\] \[K=\frac{{{p}_{(xy)}}{{p}_{(y)}}}{{{p}_{(x{{y}_{2}})}}}=\frac{200\times 200}{400}\] \[=100\]You need to login to perform this action.
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