A) \[{{V}_{1}}>{{V}_{2}}\]and \[{{Z}_{1}}<{{Z}_{2}}\]
B) \[{{V}_{1}}>{{V}_{2}}\]and \[{{Z}_{1}}>{{Z}_{2}}\]
C) \[{{V}_{1}}<{{V}_{2}}\]and\[{{Z}_{1}}>{{Z}_{2}}\]
D) \[{{V}_{1}}={{V}_{2}}\]and\[{{Z}_{1}}<{{Z}_{2}}\]
Correct Answer: A
Solution :
\[{{\lambda }_{\min }}=\frac{hc}{eV}\] \[\Rightarrow \] \[\lambda \propto \frac{1}{V}\] \[(\because {{\lambda }_{2}}>{{\lambda }_{1}})\] \[\Rightarrow \] \[{{V}_{1}}>{{V}_{2}}\] From Moseley's law\[\sqrt{v}=a(Z-b)\] \[v\propto {{(Z-1)}^{2}}\] \[\Rightarrow \] \[\lambda \propto \frac{1}{{{(Z-1)}^{2}}}\] \[\left[ \because v\propto \frac{1}{\lambda } \right]\] According to diagram\[{{\lambda }_{1}}>{{\lambda }_{2}}\] \[\Rightarrow \] \[{{Z}_{2}}>{{Z}_{1}}\]You need to login to perform this action.
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