A) 1 MeV
B) 11.9 MeV
C) 23.8 MeV
D) 931 MeV
Correct Answer: C
Solution :
Mass of\[_{1}{{H}^{2}}=\]2.01478 amu Mass of\[_{2}H{{e}^{4}}=\]400388 amu Mass of two deuterium \[=2\times 2.01478=4.02956\] Energy equivalent to 2,\[{{H}^{2}}\] \[=4.02956\times 1.112\text{ }MeV=4.48\text{ }MeV\] Energy equivalent to\[_{2}H{{e}^{4}}\] \[=4,00388\times 7.047MeV=28.21\text{ }MeV\] Energy released \[=28.21-4.48=23.73\text{ }MeV\] \[=24\text{ }MeV\]You need to login to perform this action.
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