A) \[ut-\frac{1}{2}g{{t}^{2}}\]
B) \[\frac{1}{2}g{{t}^{2}}\]
C) \[(u+gt)t\]
D) \[ut\]
Correct Answer: B
Solution :
When falling from topmost point distance travelled in t sec\[=\frac{1}{2}g{{t}^{2}}\] \[\therefore \]Distance travelled in last t sec of ascent \[=\frac{1}{2}g{{t}^{2}}\]You need to login to perform this action.
You will be redirected in
3 sec