A) 9m
B) 11 m
C) 33m
D) 40m
Correct Answer: A
Solution :
Given, \[v=kt\] Also \[k=2m{{s}^{-2}}\] \[\therefore \] \[v=2t\] or \[\frac{dx}{dt}=2t\] On integration of both sides \[x={{t}^{2}}+c\] When,\[t=0,\]then \[x=0\] \[\therefore \] \[0={{(0)}^{2}}+c\] \[\Rightarrow \] \[c=0\] So, we get \[x={{t}^{2}}\] When \[t=3~\] \[\Rightarrow \] \[x={{(3)}^{2}}=9m\]You need to login to perform this action.
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