A) \[92.2\]
B) \[29.2\]
C) \[20.2\]
D) \[2.92\]
Correct Answer: D
Solution :
Equilibrium constant\[K=\frac{{{k}_{f}}}{{{k}_{b}}}\] \[=\frac{2.38\times {{10}^{-4}}}{8.15\times {{10}^{-5}}}\] \[=2.92\]You need to login to perform this action.
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