A) fall vertically with an acceleration \[g\,m/{{s}^{2}}\]
B) fall vertically with no acceleration
C) fall vertically with an acceleration\[\left( \frac{d-\rho }{d} \right)\]
D) fall vertically with an acceleration\[\left( \frac{\rho }{d} \right)\]
Correct Answer: C
Solution :
Apparent weight = actual weight - upthrust force \[Vdg=Vdg-V\rho g\] \[g=\left( \frac{d-\rho }{d} \right)g\]You need to login to perform this action.
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