A) \[360\,\pi N\]
B) 36 N
C) \[144\pi \times {{10}^{3}}N\]
D) \[36\pi \times {{10}^{5}}N\]
Correct Answer: A
Solution :
The force required to stretch \[F=\frac{\gamma Al}{L}\] \[=\frac{9\times {{10}^{10}}\times \pi \times 4\times {{10}^{-6}}\times 0.1}{100}\] \[=360\pi N\]You need to login to perform this action.
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