Answer:
Let \[BD=x\text{ }cm\], \[DW=24\text{ }cm\], Then, \[BW=(24-x)\text{ }cm,\text{ }AE=12-4=8\text{ }cm\] In \[\Delta \,DEW,\,AB\parallel EW\] \[\therefore \frac{AD}{AE}=\frac{BD}{BW}\] [Thales? Theorem] \[\Rightarrow \frac{4}{8}=\frac{x}{24-x}\] \[\Rightarrow 8x=96-4x\] \[\Rightarrow 12x=96\] \[\Rightarrow x=\frac{96}{12}=8\,cm\] \[\therefore DB=8\,cm\]
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