Answer:
\[\angle B=90{}^\circ \] [Given] We know that in \[\Delta \text{ }ABC\], \[\angle A+\angle B+\angle C=180{}^\circ \] [Angle sum property of a \[\Delta \]] \[\Rightarrow \,\,\angle A+\angle C+90{}^\circ =180{}^\circ \] \[\Rightarrow \,\,\angle A+\angle C=180{}^\circ -90{}^\circ \] \[=90{}^\circ \] \[\therefore \sin (A+C)=sin\,90{}^\circ =1\]
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