In the given figure, ABCD is a rectangle of dimensions \[21\,cm\times 14\text{ }cm\]. A semicircle is drawn with BC as diameter. Find the area and the perimeter of the shaded region in the figure. |
Answer:
Area of shaded region = Area of rectangle \[\] Area of semi circle \[=l\times b-\frac{1}{2}\pi {{r}^{2}}\] \[=21\times 14-\frac{1}{2}\times \frac{22}{7}\times 7\times 7\] \[=294-77\] \[=217\,\,c{{m}^{2}}\] Perimeter of shaded region \[=2l+b+\pi r\] \[=2\times 21+14+\frac{22}{7}\times 7\] \[=42+14+22\] \[=78\,\,cm\]
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