Answer:
Volume of water collected in system = Volume of cylindrical tank \[L\times B\times H=\pi {{r}^{2}}h\] \[22\times 20\times H=\frac{22}{7}\times 1\times 1\times 3.5\] \[22\times 20\times H=11\] \[H=\frac{11}{22\times 20}=\frac{1}{40}m\] \[=\frac{1}{40}\times 100=\frac{5}{2}=2.5\,\,cm\] Rainfall on system \[=2.5\text{ }cm\] Water conservation is very important as it solves the water problem in the absence of rain.
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