• # question_answer An integer is chosen at random between 1 and 100. Find the probability that it is: (i) divisible by 8. (ii) not divisible by 8.

 Total numbers are 2, 3, 4, ........., 99 (i) Let E be the event of getting a number divisible by 8. $E=\{8,16,24,32,40,48,56,64,72,80,88,96\}$ $=12$ $P(E)=\frac{Favourable\,\,outcomes}{Total\,\,outcomes}$ $=\frac{12}{98}=0.1224$ (ii) Let E? be the event of getting a number not divisible by 8. Then,   $P(E)=1-P(E)$ $=\text{ }1-0.1224$ $=0.8756$