A) 3.48 kJ
B) 3.74 kJ
C) 37.4 kJ
D) 34.8 kJ
Correct Answer: B
Solution :
Given that: \[n=1\] \[T=300K\] Now by using: KE (kinetic energy) \[=\frac{3}{2}nRT\] \[=\frac{3}{2}\times 1\times 8.314\times 300\] \[=3740\text{ }Joule\] \[=3.74kJ\]You need to login to perform this action.
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