A) A
B) 2A
C) 3A
D) 4A
Correct Answer: B
Solution :
Let a and b are two numbers. Then, \[A=\frac{a+b}{2}\] ?(i) Also, a, p, q, b are in GP. \[\therefore \] \[\frac{p}{a}=\frac{q}{p}=\frac{b}{q}\] \[\Rightarrow \] \[\frac{{{p}^{2}}}{q}=a\] and \[\frac{{{q}^{2}}}{p}=b\] \[\therefore \] \[\frac{{{p}^{2}}}{q}+\frac{{{q}^{2}}}{p}=a+b=2A\] [using Eq. (i)]You need to login to perform this action.
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