A) \[c\]
B) \[d-c\]
C) \[2d\]
D) \[2c\]
Correct Answer: B
Solution :
Given, \[f(x)={{x}^{2}}+ax+b,\]then \[f(x+c)={{(x+c)}^{2}}+a(x+c)+b\] \[={{x}^{2}}+(2c+a)x+{{c}^{2}}+ac+b\] Which show roots of \[f(x)\]are transformed to \[(x-c)\]i.e., roots of \[f(x+c)=0\]are \[c-c\]and \[d-c.\] Hence, one of the roots of the equation \[f(x+c)\]is\[(d-c).\]You need to login to perform this action.
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