A) \[2.5\times {{10}^{-6}}C\]
B) \[2\times {{10}^{-6}}C\]
C) \[{{10}^{-6}}C\]
D) \[8\times {{10}^{-6}}C\]
Correct Answer: A
Solution :
\[\phi =B.A\] Change in flux \[d\phi =B.\,dA\] \[=0.05(101-100)\times {{10}^{-4}}\] \[=5\times {{10}^{-6}}Wb\] Now charge \[dQ=\frac{d\phi }{R}\] \[=\frac{5\times {{10}^{-6}}}{2}=2.5\times {{10}^{-6}}C\]You need to login to perform this action.
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