A) \[6\times {{10}^{-4}}V\]
B) \[4.8\times {{10}^{-3}}V\]
C) \[6\times {{10}^{-2}}V\]
D) \[48mV\]
Correct Answer: D
Solution :
Induced emf \[e=M\frac{di}{dt}\] \[=\frac{{{\mu }_{0}}\,{{N}_{1}}{{N}_{2}}A}{l}.\frac{di}{dt}\] \[=\frac{4\pi \times {{10}^{-7}}\times 2000\times 300\times 1.2\times {{10}^{-3}}}{0.30}\] \[\times \frac{|2-(-2)|}{0.25}\] \[=48.2\times {{10}^{-3}}V=48mV\]You need to login to perform this action.
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