A) 0.32 A
B) 0.16 A
C) 0.43 A
D) 0.80 A
Correct Answer: B
Solution :
Impedence \[Z=\sqrt{{{R}^{2}}+X_{L}^{2}}\] \[=\sqrt{{{(10)}^{2}}+{{(2\pi \times 60\times 2)}^{2}}}\] \[=753.7\] \[\therefore \] Current \[i=\frac{V}{Z}=\frac{120}{753.7}=0.159A\]You need to login to perform this action.
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