A) 0.04 J
B) 0.02 J
C) 0.025 J
D) 0.05 J
Correct Answer: B
Solution :
The energy released on discharging the capacitor fully, is given by \[E=\frac{1}{2}C{{V}^{2}}=\frac{1}{2}\times 4\times {{10}^{-6}}\times {{(100)}^{2}}\] \[=2\times {{10}^{-2}}=0.02\,J\]You need to login to perform this action.
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