A) \[9\times {{10}^{5}}\] volt
B) \[8\times {{10}^{6}}\]volt
C) 80 volt
D) 9 volt
Correct Answer: B
Solution :
Electric potential at the surface of an atomic nucleus is \[V=\frac{1}{4\pi {{\varepsilon }_{0}}}.\frac{Ze}{r}\] \[=\frac{9\times {{10}^{9}}\times 50\times 1.6\times {{10}^{-19}}}{9\times {{10}^{-15}}}\] \[=8\times {{10}^{6}}\,\text{volt}\]You need to login to perform this action.
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