A) \[\frac{2v(n-1)}{n}\]
B) \[\frac{v(n-1)}{n}\]
C) \[\frac{v(n+1)}{n}\]
D) \[\frac{2v(n+1)}{n}\]
Correct Answer: A
Solution :
Displacement in last 2S \[=\frac{1}{2}a{{n}^{2}}-\frac{1}{2}a{{(n-2)}^{2}}=2a(n-1)\] Acceleration \[a=\frac{v}{n}\] \[(\because \,t=n\,s)\] Displacement in last \[2\,s=\frac{2v\,(n-1)}{n}\]You need to login to perform this action.
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