A) \[\left[ ML{{T}^{-1}}A \right]\]
B) \[[{{M}^{2}}L{{T}^{-2}}\,{{A}^{-1}}]\]
C) \[\left[ M{{L}^{-2}}{{A}^{-1}} \right]\]
D) none of these
Correct Answer: C
Solution :
\[\vec{F}=q\vec{v}\times \vec{B}\] or \[F=q\,v\,B\,\sin \theta \] \[\therefore \] \[[B]=\left[ \frac{F}{qv} \right]=\frac{[ML{{T}^{-2}}]}{[AT][L{{T}^{-1}}]}=[M{{T}^{-2}}{{A}^{-1}}]\]You need to login to perform this action.
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