A) 16
B) 32
C) 64
D) 128
Correct Answer: D
Solution :
In an adiabatic process. \[P{{V}^{\gamma }}=\text{constant}\] or \[{{P}_{1}}V_{1}^{\gamma }={{P}_{2}}V_{2}^{\gamma }\] or \[\frac{{{P}_{2}}}{{{P}_{1}}}={{\left( \frac{{{V}_{1}}}{{{V}_{2}}} \right)}^{\gamma }}\] ?(i) Volume of gas \[=\frac{\text{Mass}}{\text{Density}}\] ie., \[V=\frac{M}{\rho }\]or \[V\propto \frac{1}{\rho }\] \[\therefore \] \[\frac{{{V}_{1}}}{{{V}_{2}}}=\frac{{{\rho }_{2}}}{{{\rho }_{1}}}=32\] Thus, form Eq.(i), we have \[\frac{{{P}_{2}}}{{{P}_{1}}}={{(32)}^{\gamma }}={{(32)}^{7/5}}={{2}^{7}}=128\]You need to login to perform this action.
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