A) (T - 4) K
B) (T + 4) K
C) (T - 2.4) K
D) (T + 2.4) K
Correct Answer: A
Solution :
Work done by gas in adiabatic process \[W=\frac{nR({{T}_{i}}-{{T}_{f}})}{\gamma -1}\] \[\therefore \] \[6R=\frac{1\times R(T-{{T}_{2}})}{{{(5/3)}^{-1}}}\] or \[6=\frac{T-{{T}_{2}}}{2/3}\] or \[T-{{T}_{2}}=4\] \[{{T}_{2}}=(T-4)k\]You need to login to perform this action.
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