A) 4, 1
B) 3, 7
C) 8, 1
D) 4, 7
Correct Answer: A
Solution :
Number of \[\alpha \] particle \[=\frac{difference\,of\,mass\,number}{4}\] \[=\frac{228-212}{4}=\frac{16}{4}=4\] Number of \[\beta \] particle \[=2\times \alpha -\] (difference of atomic numbers) \[=2\times 4-(90-83)=2\times 4-7=1\]You need to login to perform this action.
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