A) 60
B) 30
C) 70
D) 35
Correct Answer: B
Solution :
\[\,5CO+{{I}_{2}}{{O}_{5}}\to 5C{{O}_{2}}+{{I}_{2}}\] 1 mole of \[{{I}_{2}}\equiv 1\] mole of\[{{I}_{2}}{{O}_{5}}\equiv 5\] moles of CO Hence, mole of \[CO=5\times \frac{2.54}{254}=0.05\] Mass of \[CO=0.05\times 28=1.4g\] Mass of \[C{{O}_{2}}=2-1.4=0.6g\] Mass % of \[C{{O}_{2}}=\frac{0.6\times 100}{2}=30\]You need to login to perform this action.
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