A) \[~M\]
B) \[\frac{M}{2}\]
C) \[\frac{M}{5}\]
D) \[\frac{M}{3}\]
Correct Answer: C
Solution :
\[MnO_{4}^{-}+8{{H}^{+}}+5{{e}^{-}}\to M{{n}^{2+}}4{{H}_{2}}O\] Gain electrons = 5 Molecular weight = M \[Equivalent\,weight\,=\frac{molecular\,weight}{gain\,electron}=\frac{M}{5}\]You need to login to perform this action.
You will be redirected in
3 sec