A) 7.883 g
B) 3.941 g
C) 5.91 g
D) 2.645 g
Correct Answer: A
Solution :
\[N{{i}^{-}}+2{{e}^{-}}\to Ni\] (at cathode) \[Equivalent\,weight\,of\,Ni=\frac{mol.wt}{gain\,electron}\] \[=\frac{58.7}{2}\] \[=29.35\] \[i=12A,\,t=1h=60\times 60s,Z=\frac{Equ.wt.}{96500}\] \[Weight\text{ }of\text{ }deposite\text{ }Ni=\frac{Zit\,efficiency}{100}\] \[=\frac{29.35\times 12\times 60\times 60\times 60}{96500\times 100}\] \[=7.883\,g\]You need to login to perform this action.
You will be redirected in
3 sec