A) \[C{{H}_{3}}OCOC{{H}_{2}}C{{H}_{3}}\]
B) \[~C{{H}_{3}}C{{H}_{2}}OCOC{{H}_{2}}C{{H}_{3}}\]
C) \[C{{H}_{3}}C{{H}_{2}}OCOC{{H}_{3}}\]
D) \[C{{H}_{3}}C{{H}_{2}}OCOC{{H}_{2}}C{{H}_{2}}C{{H}_{3}}\]
Correct Answer: A
Solution :
Only ethyl acetate undergoes reduction with LiAlH4 to give only ethyl alcohol, other esters given in option on reduction gives a mixture of alcohols. \[C{{H}_{3}}COOC{{H}_{2}}C{{H}_{3}}+2{{H}_{2}}\xrightarrow[ether]{LiAl{{H}_{4}}}2C{{H}_{3}}C{{H}_{2}}OH\]You need to login to perform this action.
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