A) 2E
B) 4 E
C) 6E
D) 10 E
Correct Answer: B
Solution :
For 1st situation, \[E=\frac{1}{2}k{{(10\,\times \,{{10}^{-2}})}^{2}}\] ?(i) For 2nd situation, \[E=\frac{1}{2}k{{(20\times {{10}^{-2}})}^{2}}\] ?(ii) On comparing Eqs. (i) and (ii), we get \[E=4E\]You need to login to perform this action.
You will be redirected in
3 sec