A) \[D{{\left( \frac{{{L}_{2}}}{{{L}_{1}}} \right)}^{\frac{1}{2}}}days\]
B) \[D{{\left( \frac{{{L}_{2}}}{{{L}_{1}}} \right)}^{\frac{3}{2}}}days\]
C) \[D{{\left( \frac{{{L}_{2}}}{{{L}_{1}}} \right)}^{\frac{2}{3}}}days\]
D) \[D\left( \frac{{{L}_{2}}}{{{L}_{1}}} \right)days\]
Correct Answer: B
Solution :
By Keplars law, \[{{T}^{2}}\propto {{R}^{3}}\] Hence \[T=D{{\left( \frac{{{L}_{2}}}{{{L}_{1}}} \right)}^{3/2}}\]You need to login to perform this action.
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