A) \[\frac{-{{r}_{2}}}{{{r}_{1}}}q\]
B) zero
C) \[\frac{-{{r}_{1}}}{{{r}_{2}}}q\]
D) \[-q\]
Correct Answer: C
Solution :
Let, the charge on the inner shell be q The total charge will be zero So, \[\frac{kq}{{{r}_{1}}}+\frac{kq}{{{r}_{2}}}=0\] \[(\because \,{{r}_{2}}>{{r}_{1}})\] \[\Rightarrow \] \[q=-\frac{Kq/{{r}_{2}}}{K/{{r}_{1}}}\] \[q=-\left( \frac{{{r}_{1}}}{{{r}_{2}}} \right)q\]You need to login to perform this action.
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