A) \[\frac{2E}{4r+R}\]
B) \[\frac{3E}{4r+R}\]
C) \[\frac{3E}{3r+R}\]
D) \[\frac{2E}{3r+R}\]
Correct Answer: A
Solution :
Total emf of the cell \[=3E-E=2E\] Total internal resistance \[=4r\] \[\therefore \] Total resistance of the circuit \[=4r+R\] So, the current in the external circuit \[\left( \because \,i=\frac{V}{R} \right)\] \[\therefore \] \[i=\frac{2E}{4r+R}\]You need to login to perform this action.
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