A) \[{{K}_{2}}O>BaO>CaO>MgO\]
B) \[~{{K}_{2}}\text{O}>CaO>BaO>MgO\]
C) \[~~MgO>BaO>CaO>{{K}_{2}}O\]
D) \[~MgO>CaO>BaO>{{K}_{2}}O\]
Correct Answer: A
Solution :
On the basis of electropositivity of metal, the order of basic character is \[{{K}_{2}}O>BaO>CaO>MgO\]You need to login to perform this action.
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