A) \[H{{O}^{-}}\]
B) \[{{H}_{2}}O\]
C) \[{{O}_{2}}\]
D) \[O_{2}^{-}\]
Correct Answer: A
Solution :
In aqueous alkaline solution, two electron reduction of \[\text{HO}_{2}^{-}\]gives \[\bar{O}H.\]The reaction is as follows: \[{{H}_{2}}{{O}_{2}}{{H}^{+}}+HO_{2}^{-}\] \[HO_{2}^{-}+{{H}_{2}}O+2{{e}^{-}}3\bar{O}H\]You need to login to perform this action.
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