| Column 1 | Column 11 |
| A. Primitive cubic unit cell B. Body centred cubic unit cell C. Face centred cubic unit cell D. End centred orthorhombic unit cell |
1. Each of the three perpendicular edges
compulsorily have the different edge length i.e., 
2. Number of atoms per unit cell is one
3. Each of the three perpendicular edges
compulsorily have the same edge length i.e., a = b = c
4.In addition to the contribution from the corner
atoms the number of atoms present in a unit cell is one
5. In addition to the contribution from the
corner atoms the number of atoms present in a unit cell is three
|
Answer:
A. ®
(2, 3) B. ® (3, 4) C. ® (3, 5) D. ® (1, 4)
A. For primitive unit cell, a = b =
c
Total number of atoms per unit
cell = 1/8 x 8 = 1
Here, 1/8 is due to contribution
of each atom present at corner.
B. For body centred cubic unit
cell, a = b = c
This lattice contain atoms at
corner as well as body centre. Contribution due to atoms at
corner =1/ 8 x 8 =1 contribution
due to atoms at body centre = 8
C. For face centred unit cell, a
= b = c
Total constituent ions per unit
cell present at corners = 
x 8 = 1
Total constituent ions per unit
cell present at face centre = 
x 6 = 3
D. For end centered orthorhombic
unit cell, 
Total contribution of atoms
present at corner = x 8 = 1
Total contribution of atoms
present at end centre = x 2 = 1
Hence, other than corner it
contain total one atom per unit cell.
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