Answer:
. (a) Since vinyl halides are unreactive towards nucleophilic substitution reactions, therefore, \[C{{H}_{2}}=CHBr\] does not react with \[AgCN\].
\[C{{H}_{2}}=CHBr\xrightarrow[\text{alcohol}]{\text{AgCN}}\text{No}\,\text{reaction}\]
(b) The initially formed less stable \[1{}^\circ \] carbocation \[(I)\] undergoes 1, 2-methyl shift to give the more stable \[3{}^\circ \]carbocation \[(II)\]which then attacks the benzene ring to give. F.C. alkylation product \[(III),\]
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