Answer:
(i) \[3{}^\circ \]Alkyl halides on treatment with a strong base undergo dehydrohalogenation to form alkenes, i.e.,
(ii) Addition of \[{{H}^{+}}\] to 3-methyl-1-butene first gives \[2{}^\circ \] carbocation \[(I)\] which being less stable rearranges to the more stable \[3{}^\circ \] carbocation \[(II)\]. Nucleophilic attack by \[B{{r}^{-}}\] ion on this carbocation gives 2-bromo-2-methylbutane as the major product,
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