A) \[H-H\]- \[911\] \[52.15\]-\[104\]
B) \[H-H\]-\[52153\] \[52.15\]-\[Alkyne\xrightarrow[Lindlars\,\,catalyst]{{{H}_{2}}}A\xrightarrow{Ozonolysis}\underset{only}{\mathop{B}}\,\]
C) \[H-H\]-\[\xleftarrow[\Pr ocess]{Wac\ker }C{{H}_{2}}=C{{H}_{2}}\] \[52.15\]-\[{{H}_{3}}C-C\equiv C-C{{H}_{3}}\]
D) \[H-H\]-\[{{H}_{3}}C-C{{H}_{2}}-C\equiv CH\] \[52.15\]-\[{{H}_{2}}C=CH-C\equiv CH\]
Correct Answer: A
Solution :
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