question_answer 47)

Henry's law constant for the molarity of methane in benzene at 298 K is 4.27 x 105 mm Hg. Calculate the solubility of methane in benzene at 298 K under 760 mm Hg.  

Answer:

Here, kH = 4.27 x 105 mm, p° = 760 mm Applying Henry's law, p = kH.x x i.e., mole fraction of methane in benzene