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A triangle has three vertex, three angles and three sides in above figure.
vertex be A, Band C
Angle be \[\angle ABC,\] \[\angle BCA,\] and \[\angle CAB,\]or \[\angle BAC\]
According to sides, type of triangle be
(a) Equilateral Triangle: All sides are equal
(b) Isosceles Triangle: Two sides are equal
(c) Scalene Triangle: All sides are different.
According to Angle, There are three types of triangles:
(a) Acute Angle Triangle
(b) Obtuse Angle Triangle
(c) Right angle Triangle
Then \[\angle A=90{}^\circ -\theta \]
\[\sin \theta =\frac{P}{h}=\frac{AB}{AC},\,\]\[\cos ec\,\theta =\frac{h}{P}\]
\[\cos \,\theta =\frac{b}{h},\] \[sec\theta =\frac{h}{b}\]
\[\tan \theta =\frac{P}{b},\] \[\cot \theta =\frac{b}{P}\]
Trigonometrical ratio shows the relation between angle and sides of the triangle.
| \[\sin \theta \times \operatorname{cosec}\theta =1\] |
| \[\tan \theta \times \cot \theta =1\] |
| \[\cos \theta \times \sec \theta =1\] |
| \[{{\sin }^{2}}\theta =1-{{\cos }^{2}}\theta \] |
| \[{{\cos }^{2}}\theta =1-{{\sin }^{2}}\theta \] |
Angle may be positive or negative
When angle be measured in anticlockwise direction then it is positive otherwise negative.
Discontinuous Function
Continuity of a Function at a Point
A function f(x) is said to be continuous at a point x = a of its domain if and only if it satisfies the following three condition:
(i) f(a) exist. ('a' line in the domain of f)
(ii) \[\underset{x+a}{\mathop{\lim }}\,\] f(x) exist e.e; \[\underset{x\to {{a}^{+}}}{\mathop{\lim }}\,\] f(x)= \[\underset{x\to {{a}^{-}}}{\mathop{\lim }}\,\] f(x) or R.H.L= L.H.L
(iii) \[\underset{x+a}{\mathop{\lim }}\,\] f(x) = f(a) (limit equals the value of function)
Continuity from Left and Right
A function f(x) is said to be continuous at a point x = a of its domain if and only if it satisfies the following three condition:
(i) f(a) exist. ('a' line in the domain of f)
(ii) \[\underset{x+a}{\mathop{\lim }}\,\] f(x) exist e.e; \[\underset{x\to {{a}^{+}}}{\mathop{\lim }}\,\] f(x)= \[\underset{x\to {{a}^{-}}}{\mathop{\lim }}\,\] f(x) or R.H.L= L.H.L
(iii) \[\underset{x+a}{\mathop{\lim }}\,\] f(x) = f(a) (limit equals the value of function)
Cauchy's Definition of Continuity
A function f is said to be continuous at a point a of its domain D if for every \[\varepsilon >o\] there exists \[\delta >o\] (dependent of\[\varepsilon \]) such that \[\left| x-a \right|<\delta \]
\[\Rightarrow \left| \text{f}(x)-\text{f(a)} \right|<\varepsilon \]
Comparing this definition with the definition of limit we find that f(x) is continuous at x = a if \[\underset{x\to a}{\mathop{\lim }}\,\]f(x) exists and is equal to f(a) i.e; \[\underset{x\to {{a}^{-}}}{\mathop{\lim }}\,\] f(a) \[\underset{x\to {{a}^{+}}}{\mathop{\lim }}\,\] f(x).
Continuity from Left and Right
Function f(x) is said to be
(i) Left continuous at x= a if \[\underset{x\to {{a}^{-}}}{\mathop{\lim }}\,\,\,\text{f(x)=f(a)}\text{.}\]
(ii) Right continuous at x = a if \[\underset{x\to {{a}^{+}}}{\mathop{\lim }}\,\,\,\text{f(x)=f(a)}\text{.}\]
Thus a function f(x) is continuous at a point x = a if it is left continuous as well as right continuous at x = a.
Differentiation
The function, f(x) is differentiable at point P, iff there exists a unique tangent at point P. In other words, f(x) is differentiable at point P iff the curve does not have pas a corner point i.e; the function is not differentiable at those more...
Hence, we have
\[\operatorname{Re}(z)=\frac{z+\overline{z}}{2}\] and \[\operatorname{Im}(z)=\frac{z-\overline{z}}{2i}\]
\[\Rightarrow \] Geometrically, the conjugate of z is the reflection or point image of z in the real axis.
e.g.
(i) \[z=3-4i\]
\[z=3-(-4)=3+4i\]
(ii) \[z=2+5i\]
\[\overline{z}=2-5i\]
(iii) \[\overline{z}=5i\]
\[\overline{z}=-5i\]
Let \[z=x+iy\] is a complex no. It is represented as \[P(x,y).\] more... You need to login to perform this action.
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