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Step 1 : When particle is in its equilibrium position, balance all forces acting on it and locate the equilibrium position mathematically. Step 2 : From the equilibrium position, displace the particle slightly by a displacement y and find the expression of net restoring force on it. Step 3 : Try to express the net restoring force acting on particle as a proportional function of its displacement from mean position. The final expression should be obtained in the form. \[F=-\,ky\] Here we put \[-ve\] sign as direction of F is opposite to the displacement y. If a be the acceleration of particle at this displacement, we have \[a=-\,\left( \frac{k}{m} \right)\,y\]     Step 4 : Comparing this equation with the basic differential equation of S.H.M. we get \[{{\omega }^{2}}=\frac{k}{m}\]\[\Rightarrow \]\[\omega =\sqrt{\frac{k}{m}}\] or \[n=\frac{1}{2\pi }\sqrt{\frac{k}{m}}\] As \[\omega \] is the angular frequency of the particle in S.H.M., its time period of oscillation can be given as \[T=\frac{2\pi }{\omega }\]\[=2\pi \sqrt{\frac{m}{k}}\] (i) In different types of S.H.M. the quantities m and k will go on taking different forms and names. In general m is called inertia factor and k is called spring factor. Thus \[T=2\pi \sqrt{\frac{\text{Inertia factor}}{\text{Spring factor }}}\]or \[n=\frac{1}{2\pi }\sqrt{\frac{\text{Spring}\,\text{factor}}{\text{Inertia factor}}}\] (ii) In linear S.H.M. the spring factor stands for force per unit displacement and inertia factor for mass of the body executing S.H.M. and in Angular S.H.M. k stands for restoring torque per unit angular displacement and inertial factor for moment of inertia of the body executing S.H.M. For linear S.H.M. \[T=2\pi \sqrt{\frac{m}{k}}=\sqrt{\frac{m}{\text{Force/Displacement}}}\]\[=2\pi \sqrt{\frac{\,\text{Displacement}}{\text{Acceleration}}}\]

For S.H.M. (linear) Acceleration \[\propto -\] (Displacement) \[A\propto -y\]  or \[A=-{{\omega }^{2}}y\] or \[\frac{{{d}^{2}}y}{d{{t}^{2}}}=-{{\omega }^{2}}y\] or \[m\frac{{{d}^{2}}y}{d{{t}^{2}}}+ky=0\]        [As  \[\omega =\sqrt{\frac{k}{m}}\]] For angular S.H.M. \[\tau =-\,c\theta \] and \[\frac{{{d}^{2}}\theta }{d{{t}^{2}}}+{{\omega }^{2}}\theta =0\] where \[{{\omega }^{2}}=\frac{c}{I}\]  [As c = Restoring torque constant and I = Moment of inertia]  

The average value of potential energy for complete cycle is given by  \[{{U}_{average}}=\frac{1}{T}\int_{\,0}^{\,T}{U\,dt}=\frac{1}{T}\int_{\,0}^{\,T}{\frac{1}{2}m\,{{\omega }^{2}}{{a}^{2}}{{\sin }^{2}}(\omega \,t+\varphi )}\]\[=\frac{1}{4}m{{\omega }^{2}}{{a}^{2}}\] The average value of kinetic energy for complete cycle \[{{K}_{average}}=\frac{1}{T}\int_{\,0}^{\,T}{K\,dt}\]\[=\frac{1}{T}\int_{\,0}^{\,T}{\frac{1}{2}m\,{{\omega }^{2}}{{a}^{2}}{{\cos }^{2}}\omega \,t\,dt}=\frac{1}{4}m{{\omega }^{2}}{{a}^{2}}\] Thus average values of kinetic energy and potential energy of harmonic oscillator are equal and each equal to half of the total energy \[{{K}_{average}}={{U}_{average}}\]\[=\frac{1}{2}E=\frac{1}{4}m{{\omega }^{2}}{{a}^{2}}\].

(1) Potential energy : This is an account of the displacement of the particle from its mean position. (i) The restoring force \[F=-ky\] against which work has to be done. Hence potential energy U is given by \[U=\int{dU}=-\int{dW}=-\int_{\,0}^{\,x}{Fdx}=\int_{\,0}^{\,y}{ky\,dy}=\frac{1}{2}k{{y}^{2}}+{{U}_{0}}\] where \[{{U}_{0}}=\] Potential energy at equilibrium position. If   \[{{U}_{0}}=0\] then \[U=\frac{1}{2}m{{\omega }^{2}}{{y}^{2}}\]                                                        [As\[{{\omega }^{2}}=k/m\]] (ii) Also \[U=\frac{1}{2}m{{\omega }^{2}}{{a}^{2}}{{\sin }^{2}}\omega \,t\]\[=\frac{1}{4}m{{\omega }^{2}}{{a}^{2}}(1-\cos 2\omega \,t)\]   [As \[y=a\sin \omega \,t\]] Hence potential energy varies periodically with double the frequency of S.H.M. (iii) Potential energy maximum and equal to total energy at extreme positions \[{{U}_{\max }}=\frac{1}{2}k{{a}^{2}}=\frac{1}{2}m{{\omega }^{2}}{{a}^{2}}\] when \[y=\pm a\]; \[\omega \,t=\pi /2\]; \[t=\frac{T}{4}\] (iv) Potential energy is minimum at mean position \[{{U}_{\min }}=0\]         when    \[y=0\];  \[\omega \,t=0\];  \[t=0\] (2) Kinetic energy : This is because of the velocity of the particle Kinetic Energy  \[K=\frac{1}{2}m{{v}^{2}}\]\[=\frac{1}{2}m{{\omega }^{2}}({{a}^{2}}-{{y}^{2}})\]                                [As \[v=\omega \sqrt{{{a}^{2}}-{{y}^{2}}}\]] (i) Also \[K=\frac{1}{2}m{{\omega }^{2}}{{a}^{2}}{{\cos }^{2}}\omega \,t\]\[=\frac{1}{4}m{{\omega }^{2}}{{a}^{2}}(1+\cos 2\omega t)\]                        [As \[v=a\omega \,\cos \omega \,t\]] Hence kinetic energy varies periodically with double the frequency of S.H.M. (ii) Kinetic energy is maximum at mean position and equal to total energy at mean position. \[{{K}_{\max }}=\frac{1}{2}m{{\omega }^{2}}{{a}^{2}}\] when \[y=0\]; \[t=0\]; \[\omega \,t=0\] (iii) Kinetic energy is minimum at extreme position. \[{{K}_{\min }}=0\] when \[y=a\];  \[t=T/4\], \[\omega \,t=\pi /2\] (3) Total mechanical energy : Total mechanical energy always remains constant and it is equal to sum of potential energy and kinetic energy i.e. \[E=U+K\] \[E=\frac{1}{2}m{{\omega }^{2}}({{a}^{2}}-{{y}^{2}})+\frac{1}{2}m{{\omega }^{2}}{{y}^{2}}\]\[=\frac{1}{2}m{{\omega }^{2}}{{a}^{2}}\] Total energy is not a position function. (4) Energy position graph (i) At \[y=0;\,\,U=0\] and \[K=E\] (ii) At \[y=\pm a;\,\,U=E\] and \[K=0\] (iii) At \[y=\pm \frac{a}{2}\]; \[U=\frac{E}{4}\]and \[K=\frac{3E}{4}\] (iv) At \[y=\pm \frac{a}{\sqrt{2}}\]; \[U=K=\frac{E}{2}\]

(1) All the three quantities displacement, velocity and acceleration show harmonic variation with time having same period. (2) The velocity amplitude is \[\omega \] times the displacement amplitude (3) The acceleration amplitude is \[{{\omega }^{2}}\] times the displacement amplitude (4) In S.H.M. the velocity is ahead of displacement by a phase angle \[\pi /2\] (5) In S.H.M. the acceleration is ahead of velocity by a phase angle \[\pi /2\] (6) The acceleration is ahead of displacement by a phase angle of \[\pi \]   Various physical quantities in S.H.M. at different position :  
Graph Formula At mean position At extreme position
Displacement \[y=a\sin \omega \,t\] \[y=0\] \[y=\pm a\]
Velocity \[v=a\omega \cos \omega \,t\] \[=a\omega \sin (\omega \,t+\frac{\pi }{2})\] or \[v=\omega \sqrt{{{a}^{2}}-{{y}^{2}}}\] \[{{v}_{\max }}=a\omega \] \[{{v}_{\min }}=0\]
Acceleration \[A=-a{{\omega }^{2}}\sin \omega \,t\] \[=a{{\omega }^{2}}\sin (\omega \,t+\pi )\] or \[\left| A\, \right|={{\omega }^{2}}y\] more...
(1) The acceleration of the particle executing S.H.M. at any instant, is defined as the rate of change of its velocity at that instant. So acceleration  \[A=\frac{dv}{dt}=\frac{d}{dt}(a\omega \cos \omega \,t)\]\[=-{{\omega }^{2}}a\sin \omega \,t\]\[=-{{\omega }^{2}}y\]                                  [As \[y=a\sin \omega \,t\]] (2) In S.H.M. as \[\left| \,\text{Acceleration}\, \right|\,\,={{\omega }^{2}}y\] is not constant. So equations of translatory motion can not be applied. (3) In S.H.M. acceleration is maximum at extreme position (at \[y=\pm a\]). Hence \[\left| {{A}_{\max }} \right|={{\omega }^{2}}a\] when \[\left| \,\sin \,\omega \,t\, \right|=\text{maximum}=1\] i.e.  at \[t=\frac{T}{4}\]  or \[\omega t=\frac{\pi }{2}\]. From equation (ii) \[|{{A}_{\max }}|\,={{\omega }^{2}}a\]  when \[y=a\]. (i) In S.H.M. acceleration is minimum at mean position From equation (i) \[{{A}_{\min }}=0\] when \[\sin \omega \,t=0\] i.e. at \[t=0\] or \[t=\frac{T}{2}\] or \[\omega \,t=\pi \]. From equation (ii) \[{{A}_{\min }}=0\] when \[y=0\] (ii) Acceleration is always directed towards the mean position and so is always opposite to displacement i.e.,  \[A\propto -y\] Graph between acceleration (A) and displacement (y) is a straight line as shown Slope of the line \[=-{{\omega }^{2}}\]

(1) Velocity of the particle executing S.H.M. at any instant, is defined as the time rate of change of its displacement at that instant. (2) In case of S.H.M. when motion is considered from the equilibrium position, displacement \[y=a\sin \omega \,t\] So  \[v=\frac{dy}{dt}=a\omega \cos \omega \,t\]\[=a\omega \sqrt{1-{{\sin }^{2}}\omega \,t}\]\[=\omega \sqrt{{{a}^{2}}-{{y}^{2}}}\]                           [As \[\sin \omega t=y/a\]] (3) At mean position or equilibrium position \[(y=0\,\,\text{and }\,\theta =\omega t=0),\] velocity of particle is maximum and it is \[{{v}_{\max }}=a\omega \]. (4) At extreme position \[(y=\pm a\,\,\text{and}\,\,\theta =\omega t=\pi /2),\] velocity of oscillating particle is zero i.e. \[v=0\]. (5) From \[v=\omega \sqrt{{{a}^{2}}-{{y}^{2}}}\]\[\Rightarrow \] \[{{v}^{2}}={{\omega }^{2}}({{a}^{2}}-{{y}^{2}})\]\[\Rightarrow \]\[\frac{{{v}^{2}}}{{{\omega }^{2}}}={{a}^{2}}-{{y}^{2}}\] \[\Rightarrow \] \[\frac{{{v}^{2}}}{{{a}^{2}}{{\omega }^{2}}}+\frac{{{y}^{2}}}{{{a}^{2}}}=1\] This is the equation of ellipse. Hence the graph between v and y is an ellipse. For \[\omega =1,\] graph between v and y is a circle. (6) Direction of velocity is either towards or away from mean position depending on the position of particle.

(1) The displacement of a particle executing S.H.M. at an instant is defined as the distance of particle from the mean position at that instant. (2) Simple harmonic motion is also defined as the projection of uniform circular motion on any diameter of circle of reference. (3) If the projection is taken on y-axis. then from the figure  \[y=a\sin \omega \,t\]\[=a\sin \frac{2\pi }{T}t\]\[=a\sin 2\pi \,n\,t\]\[=a\sin (\omega \,t\pm \varphi )\] (i) \[y=a\sin \omega \,t\] when the time is noted from the instant when the vibrating particle is at mean position. (ii) \[y=a\cos \omega \,t\] when the time is noted from the instant when the vibrating particle is at extreme position. (iii) \[y=a\sin (\omega \,t\pm \varphi )\] when the vibrating particle is f phase leading or lagging from the mean position. (4) If the projection of P is taken on X-axis then equations of S.H.M. can be given as \[x=a\cos \,(\omega \,t\pm \varphi )\]\[=a\cos \,\left( \frac{2\pi }{T}t\pm \varphi  \right)\]\[=a\cos \,(2\pi n\,t\pm \varphi )\] (5) Direction of displacement is always away from the equilibrium position, particle either is moving away from or is coming towards the equilibrium position.  

(1) Time period (T) : It is the least interval of time after which the periodic motion of a body repeats itself. S.I. unit of time period is second. (2) Frequency (n) : It is defined as the number of oscillations executed by body per second. S.I unit of frequency is hertz (Hz). (3) Angular Frequency \[(\omega )\]: Angular frequency of a body executing periodic motion is equal to product of frequency of the body with factor \[2\pi \]. Angular frequency \[\omega =2\pi n\] Its unit is rad/sec. (4) Phase \[(\phi )\]: Phase of a vibrating particle at any instant is a physical quantity, which completely express the position and direction of motion, of the particle at that instant with respect to its mean position. In oscillatory motion the phase of a vibrating particle is the argument of sine or cosine function involved to represent the generalised equation of motion of the vibrating particle. \[y=a\sin \theta =a\sin (\omega \,t+{{\varphi }_{0}})\] here, \[\theta =\omega \,t+{{\varphi }_{0}}\]= phase of vibrating particle. \[{{\phi }_{0}}=\]Initial phase or epoch. It is the phase of a vibrating particle at \[t=0\]. (1) Same phase : Two vibrating particle are said to be in same phase, if the phase difference between them is an even multiple of \[\pi \] or path difference is an even multiple of \[(\lambda /2)\] or time interval is an even multiple of (T / 2) because 1 time period is equivalent to \[2\pi \] rad or 1 wave length \[(\lambda )\]. (2) Opposite phase : When the two vibrating particles cross their respective mean positions at the same time moving in opposite directions, then the phase difference between the two vibrating particles is \[{{180}^{o}}\]. Opposite phase means the phase difference between the particle is an odd multiple of \[\pi (say\,\,\pi ,\,\,3\pi ,\,\,5\pi ,\,\,7\pi .....)\] or the path difference is an odd multiple of          \[\lambda (\text{say}\,\,\frac{\lambda }{2},\,\frac{3\lambda }{2}\,,......)\] or the time interval is an odd multiple of (T / 2). (3) Phase difference :  If two particles performs S.H.M and their equation are \[{{y}_{1}}=a\sin (\omega \,t+{{\varphi }_{1}})\]and \[{{y}_{2}}=a\sin (\omega \,t+{{\varphi }_{2}})\] then phase difference \[\Delta \varphi =(\omega \,t+{{\varphi }_{2}})-(\omega \,t+{{\varphi }_{1}})\]\[={{\varphi }_{2}}-{{\varphi }_{1}}\]

(1) Simple harmonic motion is a special type of periodic motion, in which a particle moves to and fro repeatedly about a mean position. (2) In linear S.H.M. a restoring force which is always directed towards the mean position and whose magnitude at any instant is directly proportional to the displacement of the particle from the mean position at that instant i.e. Restoring force  \[\mu \] Displacement of the particle from mean position. \[F\propto -x\Rightarrow F=-kx\] Where k is known as force constant. Its S.I. unit is Newton/meter and dimension is \[[M{{T}^{-2}}]\]. (3) In stead of straight line motion, if particle or centre of mass of body is oscillating on a small arc of circular path, then for angular S.H.M. Restoring torque \[(\tau )\propto -\]Angular displacement \[(\theta )\]


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