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When current is passed through a junction of two different metals, the heat is either evolved or absorbed at the junction. This effect is known as Peltier effect. It is the reverse of Seebeck effect. (When a positive charge flows from high potential to low potential, it releases energy and when positive charge flows from low potential to high potential it absorbs energy.) Peltier co-efficient \[\mathbf{(\pi )}\]: Heat absorbed or liberated at the junction is directly proportional to the charge passing through the junction i.e. \[H\propto Q\Rightarrow H=\pi Q;\] where \[\pi \] is called Peltier co-efficient. It's unit is J/C or volt. Peltier co-efficient of a junction is the amount of heat absorbed or liberated per sec. When 1 amp of current is passed to the thermo couple. It is found that \[\pi =T\frac{dE}{dT}=T\times S\]; where T is in Kelvin and \[\frac{dE}{dT}=P=\] Seebeck coefficient S

(1) Definition : When the two junctions of a thermo couple are maintained at different temperatures, then a current starts flowing through the loop known as thermo electric current. The potential difference between the junctions is called thermo electric emf which is of the order of a few micro-volts per degree temperature difference \[(\mu V{{/}^{o}}C)\]. (2) Seebeck series : The magnitude and direction of thermo emf in a thermocouple depends not only on the temperature difference between the hot and cold junctions but also on the nature of metals constituting the thermo couple. (i) Seebeck arranged different metals in the decreasing order of their electron density. Few metals forming the series are as below. Sb, Fe, Cd, Zn, Ag, Au, Cr, Sn, Pb, Hg, Mn, Cu, Pt, Co, Ni, Bi (ii) Thermo electric emf is directly proportional to the distance between the two metals in series. Farther the metals in the series forming the thermo couple greater is the thermo emf. Thus maximum thermo emf is obtained for Sb-Bi thermo couple. (iii) The current flow at the hot junction of the thermocouple is from the metal occurring later in the series towards that occurring earlier, Thus, in the copper-iron thermocouple the current flows from copper (Cu) to iron (Fe) at the hot junction. This may be remembered easily by the hot coffee. (3) Variation of thermo emf with temperature : In a thermocouple as the temperature of the hot junction increases keeping the cold junction at constant temperature (say \[{{0}^{o}}C\]). The thermo emf increases till it becomes maximum at a certain temperature. (i) Thermo electric emf is given by the equation \[E=\alpha \,t+\frac{1}{2}\beta \,{{t}^{2}}\] where \[\alpha \] and \[\beta \] are thermo electric constant having units are volt/\[^{o}C\] and volt/\[^{o}{{C}^{2}}\] respectively (t = temperature of hot junction). For E to be maximum (at \[t={{t}_{n}}\]) \[\frac{dE}{dt}=0\] i.e.\[\alpha +\beta \,{{t}_{n}}=0\Rightarrow {{t}_{n}}=-\frac{\alpha }{\beta }\] (ii) The temperature of hot junction at which thermo emf becomes maximum is called neutral temperature \[({{t}_{n}})\]. Neutral temperature is constant for a thermo couple (e.g. for \[Cu-Fe,\,\,{{t}_{n}}={{270}^{o}}C\]) (iii) Neutral temperature is independent of the temperature of cold junction. (iv) If temperature of hot junction increases beyond neutral temperature, thermo emf start decreasing and at a particular temperature it becomes zero, on heating slightly further, the direction of emf is reversed. This temperature of hot junction is called temperature of inversion \[({{t}_{i}})\]. (v) Relation between \[{{t}_{n}},\,{{t}_{i}}\] and \[{{t}_{c}}\] is \[{{t}_{n}}=\frac{{{t}_{i}}+{{t}_{c}}}{2}\] (4) Thermo electric power : The rate of change of thermo emf with the change in the temperature of the hot junction is called thermoelectric power. It is also given by the slope of parabolic curve representing the variation of thermo emf with temperature of the hot junction, as discussed in previous section. The thermo electric power \[\left( \frac{dE}{dt} \right)\] is also called Seebeck coefficient. Differentiating both sides of the equation of thermo emf with respect to t, we have thermoelectric power  \[P=\frac{dE}{dt}=\frac{d}{dt}(\alpha more...

It is an arrangement in which the chemical energy is converted into electrical energy due to chemical action taking place in it. (1) Primary cell : Is that cell in which electrical energy is produced due to chemical energy. In the primary cell, chemical reaction is irreversible. This cell can not be recharged. Examples of primary cells are Voltaic cell, Daniel cell, Leclanche cell and Dry cell etc. (2) Secondary cell : A secondary cell is that cell in which the electrical energy is first stored up as a chemical energy and when the current is taken from the cell, the chemical energy is reconverted into electrical energy. In the secondary cell chemical reactions are reversible. The secondary cells are also called storage cell or accumulator. The commonly used secondary cells is lead accumulator. (3) Defects In a primary cell : In voltaic cell there are two main defects arises. Local action : It arises due to the presence of impurities of iron, carbon etc. on the surface of commercial Zn rod used as an electrode. The particles of these impurities and Zn in contact with sulphuric acid form minute voltaic cell in which small local electric currents are set up resulting in the wastage of Zn even when the cell is not sending the external current. Removal : By amalgamating Zn rod with mercury (i.e. the surface of Zn is coated with Hg). Polarisation : It arises, when the positive \[{{H}_{2}}\] ions, which are formed by the action of Zn on sulphuric acid, travel towards the Cu rod and after transferring, the positive charge converted into H2 gas atoms and get deposited in the form of neutral layer of a gas on the surface of Cu rod. This weakens the action of cell. Removal : Either by brushing the anode the remove the layer or by using a depolariser (i.e. some oxidising agent \[Mn{{O}_{2}},\,CuS{{O}_{4}}\] etc which may oxidise \[{{H}_{2}}\] into water).   Thermo electric effect of current If two wires of different metals are joined at their ends so as to form two junctions, then the resulting arrangement is called a "Thermo couple".

(1) First law : It states that the mass (m) of substance deposited at the cathode during electrolysis is directly proportional to the quantity of electricity (total charge q) passed through the electrolyte i.e. \[m\propto q\] or \[\mathbf{m=zq=zit,}\] where the constant of proportionality z is called electrochemical equivalent (E.C.E.) of the substance. Therefore we have \[m=zit\]. If \[q=1\] coulomb, then we have \[m=z\times 1\] or \[z=m\] Hence, the electrochemical equivalent of substance may be defined as the mass of its substance deposited at the cathode, when one coulomb of charge passes through the electrolyte. S.I. unit of electrochemical equivalent of a substance is kilogram\[coulom{{b}^{1}}(kg-{{C}^{1}})\].   E.C.E. for certain substances
Element Atomic weight Atomic number Valency E.C.E. (Z) in kg / C
Hydrogen 1.0008 1 1 \[10.4\times {{10}^{9}}\]
Oxygen 15.999 8 2 \[82.9\times {{10}^{9}}\]
Aluminium 26.982 more...
Current can produce or speed up chemical change, this ability of current is called chemical effect (shown by dc not by ac). (1) Electrolytes : The liquids which allows the current to pass through them and also dissociates into ions on passing current through them are called electrolytes e.g. solutions of salts, acids and bases in water, etc. Those liquids which do not allow current to pass through them are called insulators (e.g. vegetable oils, distilled water etc.) Solutions of cane sugar, glycerin, alcohol etc. are examples of non-electrolytes. (2) Electrolysis : The process of decomposition of electrolyte solution into ions on passing the current through it is called electrolysis. Practical applications of electrolysis are Electrotyping, extraction of metals from the ores, Purification of metals, Manufacture of chemicals, Production of \[{{O}_{2}}\] and \[{{H}_{2}}\], Medical applications and electroplating. (3) Electroplating : It is a process of depositing a thin layer of one metal over another metal by the method of electrolysis. The articles of cheap metals are coated with precious metals like silver and gold to make their look more attractive. The article to be electroplated is made the cathode and the metal to be deposited is made the anode. A soluble salt of the precious metal is taken as the electrolyte. (If gold is to be coated then auric chloride is used as electrolyte). (4) Voltameter : The vessel in which the electrolysis is carried out is called a voltameter. It contains two electrodes and electrolyte. It is also known as electrolytic cell. Types of voltameters
Volatameter Anode/cathode Electrolyte Deposition
Cu voltameter Cathode may be of any material but anode must be of Cu \[CuS{{O}_{4}}\] or \[CuC{{l}_{2}}\] At cathode Cu deposited
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(1) Series combination (i) Total power consumed \[\frac{1}{{{P}_{total}}}=\frac{1}{{{P}_{1}}}+\frac{1}{{{P}_{2}}}+......\] (ii) If \['n'\] bulbs are identical, \[{{P}_{total}}=\frac{P}{N}\] (iii) \[{{P}_{consumed}}\,(\text{Brightness)}\propto V\propto R\propto \frac{1}{{{P}_{rated}}}\] i.e. in series combination bulb of lesser wattage will give more bright light and p.d. appeared across it will be more. (2) Parallel combination (i) Total power consumed \[{{P}_{total}}={{P}_{1}}+{{P}_{2}}+{{P}_{3}}......+{{P}_{n}}\] (ii) If \['n'\] identical bulbs are in parallel.  \[{{P}_{total}}=nP\] (iii) \[{{P}_{consumed}}\,(\text{Brightness)}\propto {{P}_{R}}\propto i\propto \frac{1}{R}\] i.e. in parallel combination, bulb of greater wattage will give more bright light and more current will pass through it.

(1) The price of electricity consumed is calculated on the basis of electrical energy and not on the basis of electrical power. (2) The unit Joule for energy is very small hence a big practical unit is considered known as kilowatt hour (KWH) or board of trade unit (B.T.U.) or simple unit. (3) 1 KWH or 1 unit is the quantity of electrical energy which dissipates in one hour in an electrical circuit when the electrical power in the circuit is 1 KW thus \[1KWH=\text{ }1000W\times 3600\,\,\sec =3.6\times {{10}^{6}}J\]. (4) Important formulae to calculate the no. of consumed units is \[n=\frac{\text{Total }Watt\text{ }\times \text{ Total }Hours\text{ }}{1000}\]

The rate at which electrical energy is dissipated into other forms of energy is called electrical power i.e. \[P=\frac{W}{t}=Vi={{i}^{\mathbf{2}}}R=\frac{{{V}^{\mathbf{2}}}}{R}\] (1) Units : It's S.I. unit is Joule/sec or Watt Bigger S.I. units are KW, MW and HP, remember 1 HP = 746 Watt (2) Rated values : On electrical appliances (Bulbs, Heater, Geyser ... etc.). Wattage, voltage, ... etc. are printed called rated values e.g. If suppose we have a bulb of 40 W, 220 V then rated power \[({{P}_{R}})=40\,W\] while rated voltage \[({{V}_{R}})=220\,V\].  (3) Resistance of electrical appliance : If variation of resistance with temperature is neglected then resistance of any electrical appliance can be calculated by rated power and rated voltage i.e. by using \[R=\frac{V_{R}^{\mathbf{2}}}{{{P}_{R}}}\]. (4) Power consumed (illumination) : An electrical appliance (Bulb, heater, .. etc.) consume rated power \[({{P}_{R}})\] only if applied voltage \[({{V}_{A}})\] is equal to rated voltage \[({{V}_{R}})\] i.e. If  \[{{V}_{A}}={{V}_{R}}\] So \[{{P}_{consumed}}={{P}_{R}}\]. If \[{{V}_{A}}<{{V}_{R}}\] then \[{{P}_{consumed}}=\frac{V_{A}^{2}}{R}\] also we have \[R=\frac{V_{R}^{2}}{{{P}_{R}}}\] so \[{{P}_{Consumed}}(Brightness)=\left( \frac{V_{A}^{2}}{V_{R}^{2}} \right)\,.\,{{P}_{R}}\] (5) Long distance power transmission : When power is transmitted through a power line of resistance R, power-loss will be \[{{i}^{2}}R\] Now if the power P is transmitted at voltage V then \[P=Vi\]  i.e.  \[i=(P/V)\]    So,    \[\text{Power loss}=\frac{{{P}^{2}}}{{{V}^{2}}}\times R\] Now as for a given power and line, P and R are constant so \[\text{Power loss }\propto (1/{{V}^{2}})\] So if power is transmitted at high voltage, power loss will be small and vice-versa. This is why long distance power transmission is carried out at high voltage.

When some potential difference V is applied across a resistance R then the work done by the electric field on charge q to flow through the circuit in time t will be \[W=qV=Vit={{i}^{2}}Rt=\frac{{{V}^{2}}t}{R}Joule\]. This work appears as thermal energy in the resistor. Heat produced by the resistance R is \[H=\frac{W}{J}=\frac{Vit}{4\cdot 2}=\frac{{{i}^{2}}Rt}{4\cdot 2}=\frac{{{V}^{2}}t}{4\cdot 2R}Cal.\] This relation is called joules heating.

(1) To determine the internal resistance of a primary cell (i) Initially in secondary circuit key K' remains open and balancing length \[({{l}_{1}})\] is obtained. Since cell E is in open circuit so it's emf balances on length \[{{l}_{1}}\] i.e. \[E=x{{l}_{1}}\]                        ...(i) (ii) Now key K' is closed so cell E comes in closed circuit. If the process of balancing repeated again then potential difference V balances on length \[{{l}_{2}}\] i.e. \[E=x{{l}_{2}}\]                 ... (ii) (iii) By using formula internal resistance \[r=\left( \frac{E}{V}-1 \right)\,.\,R'\] \[r=\left( \frac{{{l}_{1}}-{{l}_{2}}}{{{l}_{2}}} \right)\,.\,R'\]             (2) Comparison of emf's of two cell : Let \[{{l}_{1}}\] and \[{{l}_{2}}\] be the balancing lengths with the cells \[{{E}_{1}}\] and \[{{E}_{2}}\] respectively then \[{{E}_{1}}=x{{l}_{1}}\] and \[{{E}_{2}}=x{{l}_{2}}\Rightarrow \frac{{{E}_{1}}}{{{E}_{2}}}=\frac{{{l}_{1}}}{{{l}_{2}}}\] Let \[{{E}_{1}}>{{E}_{2}}\] and both are connected in series. If balancing length is \[{{l}_{1}}\] when cell assist each other and it is \[{{l}_{2}}\] when they oppose each other as shown then : \[({{E}_{1}}+{{E}_{2}})=x{{l}_{1}}\]                          \[({{E}_{1}}-{{E}_{2}})=x{{l}_{2}}\] \[\Rightarrow \]                               \[\frac{{{E}_{1}}+{{E}_{2}}}{{{E}_{1}}-{{E}_{2}}}=\frac{{{l}_{1}}}{{{l}_{2}}}\]          or           \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{{{l}_{1}}+{{l}_{2}}}{{{l}_{1}}-{{l}_{2}}}\]    (3) Comparison of resistances : Let the balancing length for resistance \[{{R}_{1}}\] (when XY is connected) is \[{{l}_{1}}\] and let balancing length for resistance \[{{R}_{1}}+{{R}_{2}}\] (when YZ is connected) is \[{{l}_{2}}\]. Then  \[i{{R}_{1}}=x{{l}_{1}}\] and \[i({{R}_{1}}+{{R}_{2}})=x{{l}_{2}}\Rightarrow \frac{{{R}_{2}}}{{{R}_{1}}}=\frac{{{l}_{2}}-{{l}_{1}}}{{{l}_{1}}}\] (4) To determine thermo emf (i) The value of thermo-emf in a thermocouple for ordinary temperature difference is very low (\[{{10}^{-6}}\] volt). For this the potential gradient \[x\] must be also very low \[({{10}^{-4}}\,\,V/m)\]. Hence a high resistance (R) is connected in series with the potentiometer wire in order to reduce current. (ii) The potential difference across R must be equal to the emf of standard cell i.e. \[iR={{E}_{0}}\] \[\therefore \] \[i=\frac{{{E}_{0}}}{R}\] (iii) The small thermo emf produced in the thermocouple \[e=xl\] (iv) \[x=i\rho =\frac{iR}{L}\]\[\therefore \]\[e=\frac{iRl}{L}\]where L = length of potentiometer wire, \[\rho =\]resistance per unit length, \[l=\]balancing length for e  (5) Calibration of ammeter : Checking the correctness of ammeter readings with the help of potentiometer is called calibration of ammeter. (i) In the process of calibration of an ammeter the current flowing in a circuit is measured by an ammeter and the same current is also measured with the help of potentiometer. By comparing both the values, the errors in the ammeter readings are determined. (ii) For the calibration of an ammeter, \[1\,\,\Omega \] standard resistance coil is specifically used in the secondary circuit of the potentiometer, because the potential difference across \[1\,\,\Omega \] is equal to the current flowing through it i.e. \[V=i\]. (iii) If the balancing length for the emf \[{{E}_{0}}\] is \[{{l}_{0}}\] then \[{{E}_{0}}=x{{l}_{0}}\Rightarrow x=\frac{{{E}_{0}}}{{{l}_{0}}}\] (Process of standardisation) (iv) Let \[i\,'\] current flows through \[1\,\,\,\Omega \] resistance giving potential difference as \[V'=i'(1)=x{{l}_{1}}\] where \[{{l}_{1}}\] is the balancing more...


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